On Wed, Sep 12, 2012 at 04:39:48PM +0800, Richard Huang wrote: > Hi Richard, > > I want to compile guestfsd only for some guests, including centos, debian, > variable versions. But I didn't find scripts for it. Can you guide me how > to do this? I'm unclear exactly what the question is. You can compile guestfsd (just the daemon) this way: ./configure \ --enable-daemon \ --disable-appliance \ --disable-fuse \ --disable-perl \ --disable-python \ --disable-ruby \ --disable-haskell \ --disable-php \ --disable-erlang \ --disable-gobject make $ ls -l daemon/guestfsd -rwxrwxr-x. 1 rjones rjones 2073914 Sep 12 09:57 daemon/guestfsd You still have to run that command on each distro/version that you want to build a daemon for, assuming that's what you're trying to do. Try: ./configure --help | grep -E -- '--(dis|en)able' to get a list of things that can be enabled or disabled. There is no way currently to disable building the library, tools and language bindings as a whole, although arguably we should add that. Rich. -- Richard Jones, Virtualization Group, Red Hat http://people.redhat.com/~rjones libguestfs lets you edit virtual machines. Supports shell scripting, bindings from many languages. http://libguestfs.org

yes, this is what i was asking for.. but I got the below message while compiling guestfsd daemon:   configure: error: qemu must be installed Since I am compiling on a virtual machine (CentOS 6.3), there is no qemu in it. How can I compile without qemu? P.S., I've tried --without-qemu, didn't work.